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3^(5x-9)=((1)/(27))^(9x+3)
We move all terms to the left:
3^(5x-9)-(((1)/(27))^(9x+3))=0
Domain of the equation: 27)^(9x+3))!=0We add all the numbers together, and all the variables
x∈R
3^(5x-9)-((+1/27)^(9x+3))=0
We multiply all the terms by the denominator
(3^(5x-9))*27)^(9x+1+3))-((=0
We add all the numbers together, and all the variables
(3^(5x-9))*27)^(9x+4))-((=0
We add all the numbers together, and all the variables
(3^(5x-9))*27)^(9x=0
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